Copyright: 1996 - 2024
BSEE - KB3UON
RF Cafe began life in 1996 as "RF Tools" in an AOL screen name web space totaling
2 MB. Its primary purpose was to provide me with ready access to commonly needed
formulas and reference material while performing my work as an RF system and circuit
design engineer. The World Wide Web (Internet) was largely an unknown entity at
the time and bandwidth was a scarce commodity. Dial-up modems blazed along at 14.4 kbps
while tying up your telephone line, and a nice lady's voice announced "You've Got
Mail" when a new message arrived...
All trademarks, copyrights, patents, and other rights of ownership to images
and text used on the RF Cafe website are hereby acknowledged.
My Hobby Website:
power measurement - RF Cafe Forums
RF Cafe Forums closed its virtual doors in 2012 mainly due to other social media
platforms dominating public commenting venues. RF Cafe Forums began sometime around
August of 2003 and was quite well-attended for many years. By 2010, Facebook and
Twitter were overwhelmingly dominating online personal interaction, and RF Cafe
Forums activity dropped off precipitously. If the folks at
phpBB would release a version with integrated
sign-in from the major social media platforms, I would resurrect the RF Cafe Forums,
but until then it is probably not worth the effort. Regardless, there are still
lots of great posts in the archive that ware worth looking at.
Below are the old forum threads, including responses to the original posts.
|-- Amateur Radio
Gripes & Humor
-- CAE, CAD, &
Test & Measurement
Post subject: power measurement
Sat May 08, 2004 4:05 am
May 07, 2004 6:22 am
I found your notes on the internet very
useful. I was wondering if
I may ask a small
question regarding the calculation of real
dissipation from a simple R & L
components circuit connected
in series and
powered by a an AC square wave. The
I have is:
Power supply DC Voltage :V_dc
Power supply DC current
RMS current through the circuit :I_rms
I simply wanted
to know, why is the "real power " equal to V_dc*I_dc and
Thank you very much for your time and guidance.
I am regreted
postPosted: Thu Jun 17, 2004 11:22 am
A good question. I can't
reply, but I am considering to give a try.
Unread postPosted: Wed Jun 30, 2004 8:08
the thing is why would you say the circuit is powered by
an AC square wave when you are using a DC power supply?