December 1970 Popular Electronics
Table
of Contents
Wax nostalgic about and learn from the history of early electronics. See articles
from
Popular Electronics,
published October 1954  April 1985. All copyrights are hereby acknowledged.

Here is a fairly simple quiz on AC circuit
analysis. If you are not already comfortable with adding series and parallel circuits containing resistors,
capacitors, and inductors, you will appreciate the simple formula presented that will keep the sweat
level down ;) OK, pick up you pencils... now.
Quiz on AC Circuit Theory
By Robert P. Balin
Voltage measurements made in a series ac circuit seldom add up as simply as they do in a dc circuit.
You may even find the voltage across a coil or capacitor to be greater than the supply voltage! Nevertheless,
Ohm's Law and Kirchhoff's Law do apply, and careful measurements will show that the supply voltage and
the various voltage drops around a series ac circuit are related in an unusual way: the square of the
supply voltage is equal to the square of the difference between the voltage on the coil and the voltage
on the capacitor, plus the square of the voltage on the resistor.
This relationship, (V_{Total})^{2} = (V_{L}  V_{C})^{2}
+ (V_{R})^{2},can be used to find any unknown voltage if all others are known.
In parallel ac circuits, the currents add up the same way as voltages do in a series ac circuit.
Brush up on your ac theory and see if you can solve the missing voltage or current in the circuits below.
Where necessary, the voltages and currents are related by the 3:4:5 ratio to provide easy, whole number
answers. Only simple algebra is required. Vectors, phasors, and quadratic equations are not necessary
to find the solutions.
(See answers below)
Circuit Quiz Answers
1. (10)^{2}= (8)^{2} + (VR)^{2}; VR = 6V
2. (20)^{2}= (7+VC)^{2}+ (12)^{2}; VC = 9V
3. (24)^{2}= (VL6)^{2}; VL = 30V
4. (15)^{2}= (350350)^{2}+ (VR)^{2}; VR = 15V
5. (VT)^{2}= (153)^{2}+ (16)^{2}; VT = 20V
6. (50)^{2}= (VL)^{2}+ (12)^{2}= (VC)^{2}+ (12)2; VL = VC
(VT)^{2}= (VLVC)^{2}+ (12)^{2}; VT = 12V
7. (IT)^{2}= (6)^{2}+ (8)^{2}; IT = 10 mA.
8. (20)^{2}= (16IC)^{2}+ (16)^{2}; IC = 4 mA.
9. (IT)^{2}= (1713)^{2}+ (3)^{2}; IT = 5 mA.
10. (9)^{2}= (404IC)^{2}; IC = 7 mA.
Posted June 21, 2013
