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Quiz on AC Circuit Theory
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Here is a fairly simple quiz on AC circuit analysis. If you are not already comfortable with adding series and parallel circuits containing resistors, capacitors, and inductors, you will appreciate the simple formula presented that will keep the sweat level down ;-) OK, pick up you pencils... now. Quiz on AC Circuit Theory By Robert P. Balin Voltage measurements made in a series ac circuit seldom add up as simply as they do in a dc circuit. You may even find the voltage across a coil or capacitor to be greater than the supply voltage! Nevertheless, Ohm's Law and Kirchhoff's Law do apply, and careful measurements will show that the supply voltage and the various voltage drops around a series ac circuit are related in an unusual way: the square of the supply voltage is equal to the square of the difference between the voltage on the coil and the voltage on the capacitor, plus the square of the voltage on the resistor. This relationship, (VTotal)2 = (VL - VC)2 + (VR)2,can be used to find any unknown voltage if all others are known. In parallel ac circuits, the currents add up the same way as voltages do in a series ac circuit. Brush up on your ac theory and see if you can solve the missing voltage or current in the circuits below. Where necessary, the voltages and currents are related by the 3:4:5 ratio to provide easy, whole number answers. Only simple algebra is required. Vectors, phasors, and quadratic equations are not necessary to find the solutions. (See answers below)
See answers below. Popular Electronics published many quizzes over the years - some really simple and others not so simple. Robert Balin created many of the quizzes. This is a listing of all I have posted thus far.
Circuit Quiz Answers 1. (10)2= (8)2 + (VR)2; VR = 6V 2. (20)2= (7+VC)2+ (12)2; VC = 9V 3. (24)2= (VL-6)2; VL = 30V 4. (15)2= (350-350)2+ (VR)2; VR = 15V 5. (VT)2= (15-3)2+ (16)2; VT = 20V 6. (50)2= (VL)2+ (12)2= (VC)2+ (12)2; VL = VC (VT)2= (VL-VC)2+ (12)2; VT = 12V 7. (IT)2= (6)2+ (8)2; IT = 10 mA. 8. (20)2= (16-IC)2+ (16)2; IC = 4 mA. 9. (IT)2= (17-13)2+ (3)2; IT = 5 mA. 10. (9)2= (40-4-IC)2; IC = 7 mA.
Posted June 21, 2013 |
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 Copyright: 1996 - 2018 Webmaster: Kirt Blattenberger, BSEE - KB3UON |
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RF Cafe began life in 1996 as "RF Tools" in an AOL screen name web space totaling 2 MB. Its primary purpose was to provide me with ready access to commonly needed formulas and reference material while performing my work as an RF system and circuit design engineer. The Internet was still largely an unknown entity at the time and not much was available in the form of WYSIWYG ... All trademarks, copyrights, patents, and other rights of ownership to images and text used on the RF Cafe website are hereby acknowledged. My Hobby Website: AirplanesAndRockets.com
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