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What's Your EQ?
November 1966 Radio-Electronics

November 1966 Radio-Electronics

November 1966 Radio-Electronics Cover - RF Cafe Website[Table of Contents]

Wax nostalgic about and learn from the history of early electronics. See articles from Radio-Electronics, published 1930-1988. All copyrights hereby acknowledged.

E.D. Clark has provided two new "What's Your EQ" circuit puzzlers in this November 1966 edition of Radio-Electronics magazine. EQ, by the way, stands for Electronics Quotient (play on IQ, Intelligence Quotient). That might be stating the obvious, but some newer readers might not be familiar with it. Anywho[sic], the Series Circuit challenge should be pretty easy for most people familiar with first-semester circuit analysis. Connections requires a bit of trial and error to arrive at the answer. There might be more than one set of series-parallel combinations which will produce the requires 11 Ω from combining six 13 Ω resistors. Have fun.

What's Your EQ?

"What's Your EQ?, November 1966 Radio-Electronics - RF Cafe WebsiteConducted by E. D. Clark

Two puzzlers for the student, theoretician and practical man. Simple? Double-check your answers before you say you've solved them. If you have an interesting or unusual puzzle (with an answer) send it to us. We will pay $10 for each one accepted. We're especially interested in service stinkers or engineering stumpers on actual electronic equipment. We get so many letters we can't answer individual ones, but we'll print the more interesting solutions - ones the original authors never thought of.

Write EQ Editor, Radio-Electronics, 154 West 14th Street, New York, N. Y. 10011.

Answers to this month's puzzles are on page 105.

Series Circuit - RF Cafe WebsiteSeries Circuit

In the diagram, the ammeter reads 1 amp, voltmeter (V1) reads 6 volts and voltmeter (V2) reads 8 volts.

Can you determine the resistance of R1, R2 and R3?

- James C. Bentley

 

Connections

You have six 13-ohm resistors. How can they be connected so that the resulting resistance is 11 ohms?

- Robert F. Wallace


Quizzes from vintage electronics magazines such as Popular Electronics, Electronics-World, QST, Radio-Electronics, and Radio News were published over the years - some really simple and others not so simple. Robert P. Balin created most of the quizzes for Popular Electronics. This is a listing of all I have posted thus far.

RF Cafe Quizzes

Vintage Electronics Magazine Quizzes

Vintage Electronics Magazine Quizzes

What's Your EQ? Solutions

These are the answers.

Series Circuit

With a series current of 1 amp, the drop across the 10-ohm resistor is 10 volts. This leaves 10 volts across R1 + R2 + R3 which have a total resistance of 10 ohms.

The drop across R1 + R2 is 6 volts.

Therefore, the drop across R3 is 4 volts and its resistance is 4 ohms.

The drop across R2 + R3 is 8 volts.

Therefore, the drop across R1 is 2 volts and its resistance is 2 ohms.

The drop across R2 is 4 volts and its resistance is 4 ohms.

Connections - RF Cafe WebsiteConnections

The resistors are connected as shown in Fig. 1.

Note: As shown redrawn in Fig. 2, the circuit amounts to an unbalanced bridge. R1 could also be paralleled across either R2, R5 or R6 with no change in the total resistance. Possibly the easiest proof is by the loop-current method.

 

Correction

The solution to the "Tapered Network" puzzler (August  1966 EQ) contains an error. The first equation should read:

R = 1 + (¼R)/(½ + ½R)

Otherwise, it is correct as printed.

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